(A) The starting material is methyl $p$-methylbenzoate $(CH_3-C_6H_4-COOCH_3)$. The target product is $N$-methyl-$p$-methylbenzamide $(CH_3-C_6H_4-CON

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$H_3O^{+}$; $SOCl_2$; $CH_3NH_2$

(A) The starting material is methyl $p$-methylbenzoate $(CH_3-C_6H_4-COOCH_3)$. The target product is $N$-methyl-$p$-methylbenzamide $(CH_3-C_6H_4-CONHCH_3)$.$1$. First,the ester is hydrolyzed using acid $(H_3O^{+})$ to form $p$-methylbenzoic acid $(CH_3-C_6H_4-COOH)$.$2$. Next,the carboxylic acid is treated with thionyl chloride $(SOCl_2)$ to form the corresponding acid chloride $(CH_3-C_6H_4-COCl)$.$3$. Finally,the acid chloride reacts with methylamine $(CH_3NH_2)$ to form the amide $(CH_3-C_6H_4-CONHCH_3)$.Thus,the correct sequence is $H_3O^{+}$; $SOCl_2$; $CH_3NH_2$.

Class 12 Chemistry 2 Aldehydes, Ketones and Carboxylic Acids: Carboxylic Acids and their Derivatives Mix Examples-Carboxylic acids and Their derivative

Medium

Choose the best sequence of reactions for the transformation given. Semicolons indicate separate reaction steps to be used in the order shown.

A
$H_3O^{+}$; $SOCl_2$; $CH_3NH_2$
B
$HO^{-}/H_2O$; $PBr_3$; $Mg$; $CO_2$; $H_3O^{+}$; $SOCl_2$; $CH_3NH_2$
C
$LiAlH_4$; $H_2O$; $HBr$; $Mg$; $CO_2$; $H_3O^{+}$; $SOCl_2$; $CH_3NH_2$
D
None of these would yield the desired product

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2 Aldehydes, Ketones and Carboxylic Acids: Carboxylic Acids and their Derivatives

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Mix Examples-Carboxylic acids and Their derivative

The major product in the following reaction is

DifficultTS EAMCET 2018

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Assertion: Acetamide has a more polar $C=O$ group than ethyl acetoacetate.
Reason: $-\ddot{N}H_{2}$ is more electron-donating than $-\ddot{O}C_{2}H_{5}$.

DifficultAIIMS 2007

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Consider the following sequence of reactions to give the major product $(X)$: $(i)$ $CH_3Cl$ / anhydrous $AlCl_3$, (ii) $Cl_2$ / $FeCl_3$, (iii) $K_2Cr_2O_7$ / $H_2SO_4$. $P$ g of the major product $(X)$ formed is reacted with $NaHCO_3$ solution to liberate a gas which occupied $11.2 \ dm^3$ at $STP$. $P = \text{ . . . . . . }$ g.

DifficultJEE MAIN 2026

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Identify the final product $(D)$ in the following reaction sequence:
Phthalic anhydride $\xrightarrow{PCl_5} (A)$ $\xrightarrow{LiAlH_4} (B)$ $\xrightarrow{PCC} (C)$ $\xrightarrow{HO^-, \Delta} (D)$

Difficult

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Ethanol on reaction with alkaline $KMnO_4$ gives $X$,which when reacted with methanol in the presence of an acid gives a sweet-smelling compound $Y$. $X$ and $Y$ respectively are:

MediumKVPY 2009

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Choose the best sequence of reactions for the transformation given. Semicolons indicate separate reaction steps to be used in the order shown.

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The major product in the following reaction is

Assertion: Acetamide has a more polar $C=O$ group than ethyl acetoacetate.Reason: $-\ddot{N}H_{2}$ is more electron-donating than $-\ddot{O}C_{2}H_{5}$.

Identify the final product $(D)$ in the following reaction sequence:Phthalic anhydride $\xrightarrow{PCl_5} (A)$ $\xrightarrow{LiAlH_4} (B)$ $\xrightarrow{PCC} (C)$ $\xrightarrow{HO^-, \Delta} (D)$

Ethanol on reaction with alkaline $KMnO_4$ gives $X$,which when reacted with methanol in the presence of an acid gives a sweet-smelling compound $Y$. $X$ and $Y$ respectively are:

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Assertion: Acetamide has a more polar $C=O$ group than ethyl acetoacetate.
Reason: $-\ddot{N}H_{2}$ is more electron-donating than $-\ddot{O}C_{2}H_{5}$.

Identify the final product $(D)$ in the following reaction sequence:
Phthalic anhydride $\xrightarrow{PCl_5} (A)$ $\xrightarrow{LiAlH_4} (B)$ $\xrightarrow{PCC} (C)$ $\xrightarrow{HO^-, \Delta} (D)$